在同一行的特定单词之后提取一个单词 [英] Extract one word after a specific word on the same line

问题描述

如何提取Linux(csh)中某个特定单词之后的单词? 更确切地说，我有一个文件，其中只有一行看起来像这样:

How can I extract a word that comes after a specific word in Linux (csh)? More precisely, I have a file which has a single line which looks like this:

[some useless data] --pe_cnt 100 --rd_cnt 1000 [some more data]

我想提取在--pe_cnt单词后面的数字 100 . 我不能使用sed，因为只有当您要提取整行时才可以使用sed.也许我可以使用awk?

I want to extract the number 100 which is after the --pe_cnt word. I cannot use sed as that works only if you want to extract an entire line. Maybe I can use awk?

此外，我有多个文件，它们具有不同的值而不是100，因此我需要一些提取值但不依赖于值的文件.

Also, I have multiple files that have different values instead of 100 so I need something that extracts the value but doesn't depend on the value.

推荐答案

使用awk:

awk '{for(i=1;i<=NF;i++) if ($i=="--pe_cnt") print $(i+1)}' inputFile

基本上遍历该行的每个单词.当您找到要查找的第一个单词时，抓住下一个单词并打印出来.

Basically loop over each word of the line. When you find the first you are looking for, grab the next word and print it.

使用grep:

grep -oP "(?<=--pe_cnt )[^ ]+" inputFile

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