使用bash从文本文件中提取变量的值 [英] extracting a variable's value from text file using bash
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问题描述
我正在使用Linux和bash. 我有一个简单的文本文件,如下所示:
I am using Linux and bash. I have a simple text file like below:
VAR1=100
VAR2=5
VAR3=0
VAR4=99
我想通过bash提取VAR2的值,即5.
I want to extract by means of bash the value of VAR2, that is 5.
我该怎么办?
推荐答案
最简单的方法可能是使用source
或只是.
来读取和执行文件.这将适用于您的示例,因为变量值中没有空格.否则,您需要使用grep + cut或awk,如其他答案所述.
The simplest way might be to use source
or simply .
to read and execute the file. This would work with your example, because there are no spaces in the variable values. Otherwise you need to use grep + cut or awk, as stated in other answers.
. /path/to/your/file
echo $VAR2
如dawg所述,这将使脚本中的其他变量也可用,并且可能会覆盖现有变量.
[edit] As stated by dawg, this would make the other variables available in your script too, and possibly overwrite existing variables.
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