如何使在批处理文件%*轮班工作 [英] How to make SHIFT work with %* in batch files
问题描述
在Windows XP上我的批处理文件,我想用%*
扩大到所有的参数除了第一。
的测试文件( foo.bat 的):
In my batch file on Windows XP, I want to use %*
to expand to all parameters except the first.
Test file (foo.bat):
@echo off
echo %*
shift
echo %*
电话:
C:\> foo a b c d e f
实际结果:
a b c d e f
a b c d e f
期望结果:
a b c d e f
b c d e f
我怎样才能达到预期的效果?谢谢!
How can I achieve the desired result? Thanks!!
推荐答案
那岂不是美好的,如果CMD.EXE的工作这样!不幸的是,不是一个好的语法,将你想要做什么。你能做的最好的就是你自己解析命令行,并建立一个新的参数列表。
Wouldn't it be wonderful if CMD.EXE worked that way! Unfortunately there is not a good syntax that will do what you want. The best you can do is parse the command line yourself and build a new argument list.
这样的事情能正常工作。
Something like this can work.
@echo off
setlocal
echo %*
shift
set "args="
:parse
if "%~1" neq "" (
set args=%args% %1
shift
goto :parse
)
if defined args set args=%args:~1%
echo(%args%
但是,如果一个参数包含特殊字符,如 ^
,&功放上面有问题;
,>
,<
, |
即逃走的,而不是引用
But the above has problems if an argument contains special characters like ^
, &
, >
, <
, |
that were escaped instead of quoted.
参数处理是Windows批处理编程的许多薄弱环节之一。对于几乎所有的解决方案,存在导致问题的一个例外。
Argument handling is one of many weak aspects of Windows batch programming. For just about every solution, there exists an exception that causes problems.
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