最短DOS批处理文件code获取设置为一个变量文件的第一行？ [英] Shortest DOS batch file code to get first line of a file set to a variable?

问题描述

我要寻找，将得到一个文本文件的第一行，并将其设置为DOS / Windows中的DOS变量code可能的最短时间。

有很多这样的事情在其他线程在这个StackExchange网站的例子，但我的不可以寻找如何循环并显示文件中的所有行。我要的是刚刚的简单获取的第一行。

解决方案

 设置/对VAR =＆LT; TEXT.TXT
回声％VAR％
 

从引用：<一href=\"http://forums.techguy.org/software-development/551867-batch-file-read-line-text.html\">http://forums.techguy.org/software-development/551867-batch-file-read-line-text.html
具有讽刺意味的​​海报能拿到第一线，而是通过整个文件要循环！

I am looking for the shortest amount of DOS code possible that will get the first line of a text file and set it to a variable in DOS/Windows.

There are lots of examples of this kind of thing in other threads on this StackExchange site but I am not looking for how to loop through and display all lines in a file. What I want is to just simply get the first line.

解决方案

set /p var= <Text.txt
echo %var%

Referenced from: http://forums.techguy.org/software-development/551867-batch-file-read-line-text.html Ironically the poster is able to get the first line but wanted to loop through the whole file!

这篇关于最短DOS批处理文件code获取设置为一个变量文件的第一行？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！