Haskell - 参数太少 [英] Haskell - too few arguments

问题描述

我想编写一个Haskell程序来计算两个给定数字之间的数字总和。
我有以下代码：

I want to write a Haskell program that calculates the sum of numbers between 2 given numbers. I have the following code:

sumInt :: Int -> Int -> Int
sumInt x y
   | x > y = 0
   | otherwise = x + sumInt x+1 y

但是当我编译它时，出现以下错误： / b>

But when I compile it I get the following error:

SumInt适用于太少的参数。

SumInt is applied to too few arguments.

<我不明白我做错了什么。任何想法？

I don't understand what I'm doing wrong. Any ideas?

推荐答案

您需要在 x + 1 / p>

You need parentheses around x+1:

| otherwise = x + sumInt (x + 1) y

原因是函数应用程序绑定比运营商，所以无论何时您看到

The reason is that function application binds more tightly than operators, so whenever you see

f x <> y

这总是被解析为

(f x) <> y

并且从不作为

and never as

f (x <> y)

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