data.Split（vbCrLf）的问题 [英] problem with data.Split(vbCrLf)

问题描述

您好，


我正在尝试解析换行符上的字符串。我认为vbCrLf是一个字符串常量。如何在换行符char上解析我的

字符串 - 数据？

....

data + = ASCII.GetString（buffer ，0，bytesRead）

....

Dim parts（）As String = data.Split（vbCrLf）


谢谢，

Ron

解决方案

嗨罗恩，


我认为字符串对象的拆分方法可以使用单个字符或

一个字符数组。如果你使用后者的重载，.NET将假设

数组中的任何字符都有资格作为分隔字符，因此如果你传递给CrLf，它决定了Cr OR Lf是一个分隔符。这意味着

你将得到一个空白字符串，用于

parts（）数组中的每个其他元素。


我一直使用的方式是很好的'''''''''''''''''''''''''''''''''''''''''''''''''''''''''$ $ $ $ $ $ $ $ b b b b b b b b b b （）As String = Split（data，vbCrLf）


问候，

Alex Clark

" Ron" <一个******* @ discussions.microsoft.com>在消息中写道

news：17 **************************** @ phx.gbl ... < blockquote class =post_quotes>你好，

我试图在换行符char上解析一个字符串。我猜测vbCrLf是一个字符串常量。如何在换行符char上解析我的
字符串 - 数据？
数据+ = ASCII.GetString（缓冲区，0，bytesRead）
...
Dim parts（）As String = data.Split（vbCrLf）

谢谢，
Ron

您可以使用StringReader逐行读取字符串：


Dim sr作为新的StringReader（sStringToRead）

而sr.peek<> -1

Dim s as string = sr.ReadLine

''用s做点什么

end


也许这会对你有所帮助

谢谢。我想到了，但我想我会检查

，看看我是否在vb.net中遗漏了一些东西。猜猜

我必须导入Microsoft.VisualBasice命名空间吗？


再次感谢，

Ron

-----原始消息-----
嗨罗恩，

我认为字符串对象的Split方法要么是
采用单个字符或字符数组。如果你使用后者的重载，.NET
将假设数组中的任何字符都有资格作为分隔
字符，因此如果你传入CrLf它决定Cr或Lf是
分隔器。这意味着你最终将为parts（）数组中的每个其他元素
添加一个空白字符串。

我总是使用的方式是好的'''''''''''''''''''''''''''''''''''''''' $ b函数，因为这正是你想要的，例如：

Dim parts（）As String = Split（data，vbCrLf）

问候，
Alex Clark

" Ron" <一个******* @ discussions.microsoft.com>写在
messagenews：17 **************************** @ phx.gbl ...

您好，

我正在尝试解析换行符上的字符串。我猜测vbCrLf是一个字符串常量。如何在换行符char上解析我的
字符串 - 数据？
数据+ = ASCII.GetString（缓冲区，0，bytesRead）
...
Dim parts（）As String = data.Split（vbCrLf）

谢谢，
Ron

。

Hello,

I am trying to parse a string on the newline char. I
guess vbCrLf is a string constant. How can I parse my
string - data - on the newline char?
....
data += ASCII.GetString(buffer, 0, bytesRead)
....
Dim parts() As String = data.Split(vbCrLf)

Thanks,
Ron

解决方案

Hi Ron,

I think the Split method of the string object either takes a single char or
an array of chars. If you use the latter overload, .NET will assume that
any of the chars in the array qualify as a separating character, hence if
you pass in CrLf it decides that either Cr OR Lf is a separator. This means
you''ll end up with a blank string for every other element in the array of
parts().

The way I always use is the good ol'' fashioned VB Split function, as this
does exactly what you want, eg:

Dim parts() As String = Split(data, vbCrLf)

Regards,
Alex Clark
"Ron" <an*******@discussions.microsoft.com> wrote in message
news:17****************************@phx.gbl...

Hello,

I am trying to parse a string on the newline char. I
guess vbCrLf is a string constant. How can I parse my
string - data - on the newline char?
...
data += ASCII.GetString(buffer, 0, bytesRead)
...
Dim parts() As String = data.Split(vbCrLf)

Thanks,
Ron

You can use a StringReader to read a string line by line:

Dim sr As new StringReader(sStringToRead)
while sr.peek <> -1
Dim s as string = sr.ReadLine
''Do something with s here
end While

Perhaps this will help you

Thanks. I thought about that, but I thought I would check
to see if maybe I was missing something in vb.net. Guess
I have to import the Microsoft.VisualBasice namespace?

Thanks again,
Ron

-----Original Message-----
Hi Ron,

I think the Split method of the string object either takes a single char oran array of chars. If you use the latter overload, .NET will assume thatany of the chars in the array qualify as a separating character, hence ifyou pass in CrLf it decides that either Cr OR Lf is a separator. This meansyou''ll end up with a blank string for every other element in the array ofparts().

The way I always use is the good ol'' fashioned VB Split function, as thisdoes exactly what you want, eg:

Dim parts() As String = Split(data, vbCrLf)

Regards,
Alex Clark
"Ron" <an*******@discussions.microsoft.com> wrote in messagenews:17****************************@phx.gbl...

Hello,

I am trying to parse a string on the newline char. I
guess vbCrLf is a string constant. How can I parse my
string - data - on the newline char?
...
data += ASCII.GetString(buffer, 0, bytesRead)
...
Dim parts() As String = data.Split(vbCrLf)

Thanks,
Ron

.

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